php用两个经纬度计算距离的方法
发布时间:2023-06-19 13:28:24 所属栏目:PHP教程 来源:
导读:<?PHP
function getdistanceBetweenPointsNew($latitude1,$longitude1,$latitude2,$longitude2) {
$theta = $longitude1 - $longitude2;
$miles = (sin(deg2rad($latitude1)) * sin(deg2rad($lati
function getdistanceBetweenPointsNew($latitude1,$longitude1,$latitude2,$longitude2) {
$theta = $longitude1 - $longitude2;
$miles = (sin(deg2rad($latitude1)) * sin(deg2rad($lati
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<?PHP function getdistanceBetweenPointsNew($latitude1,$longitude1,$latitude2,$longitude2) { $theta = $longitude1 - $longitude2; $miles = (sin(deg2rad($latitude1)) * sin(deg2rad($latitude2))) + (cos(deg2rad($latitude1)) * cos(deg2rad($latitude2)) * cos(deg2rad($theta))); $miles = acos($miles); $miles = rad2deg($miles); $miles = $miles * 60 * 1.1515; $feet = $miles * 5280; $yards = $feet / 3; $kilometers = $miles * 1.609344; $meters = $kilometers * 1000; return compact('miles','feet','yards','kilometers','meters'); } $point1 = array('lat' => 40.770623,'long' => -73.964367); $point2 = array('lat' => 40.758224,'long' => -73.917404); $distance = getdistanceBetweenPointsNew($point1['lat'],$point1['long'],$point2['lat'],$point2['long']); foreach ($distance as $unit => $value) { echo $unit.': '.number_format($value,4).'<br />'; } ?> (编辑:驾考网) 【声明】本站内容均来自网络,其相关言论仅代表作者个人观点,不代表本站立场。若无意侵犯到您的权利,请及时与联系站长删除相关内容! |
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